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73 lines
2.7 KiB
73 lines
2.7 KiB
7 months ago
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/*
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* Copyright (c) 2015, Intel Corporation
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* All rights reserved.
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*
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* Redistribution and use in source and binary forms, with or without modification,
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* are permitted provided that the following conditions are met:
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*
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* 1. Redistributions of source code must retain the above copyright notice, this
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* list of conditions and the following disclaimer.
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*
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* 2. Redistributions in binary form must reproduce the above copyright notice,
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* this list of conditions and the following disclaimer in the documentation and/or
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* other materials provided with the distribution.
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*
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* 3. Neither the name of the copyright holder nor the names of its contributors
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* may be used to endorse or promote products derived from this software without
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* specific prior written permission.
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*
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* THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND CONTRIBUTORS "AS IS" AND
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* ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE IMPLIED
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* WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE ARE
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* DISCLAIMED. IN NO EVENT SHALL THE COPYRIGHT HOLDER OR CONTRIBUTORS BE LIABLE FOR
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* ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES
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* (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES;
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* LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED AND ON
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* ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY, OR TORT
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* (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT OF THE USE OF THIS
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* SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE.
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*/
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#include <algorithm>
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#include <type_traits>
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#include "Iterator.hpp"
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#include <cassert>
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namespace utility
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{
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/**
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* Raw copy of one variable to another of the same size
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*
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* This can be regarder as a reinterpret_cast but does a copy and does not
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* break strict-aliasing rules.
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*
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* The source and the destination must have the same storage size (e.g. copying
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* a uint8_t into a uint32_t won't compile)
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*
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* @tparam Source The source type
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* @tparam Destination the destination type (even if it is a reference, this
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* function returns by copy)
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* @param source Source variable
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* @returns the source, reinterpreted as the destination type
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*/
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template <class Destination, class Source>
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typename std::remove_reference<Destination>::type binaryCopy(const Source source)
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{
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static_assert(sizeof(Source) == sizeof(Destination),
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"Source and Destination must have the same size");
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using Destination_ = decltype(binaryCopy<Destination>(source));
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union
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{
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Source source;
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Destination_ destination;
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} hack;
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hack.source = source;
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return hack.destination;
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}
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} // namespace utility
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