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90 lines
2.2 KiB
90 lines
2.2 KiB
// RUN: %clang_cc1 -std=c++11 -verify %s
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// Check that we deal with cases where the instantiation of a class template
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// recursively requires the instantiation of the same template.
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namespace test1 {
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template<typename T> struct A {
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struct B { // expected-note {{not complete until the closing '}'}}
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B b; // expected-error {{has incomplete type 'test1::A<int>::B'}}
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};
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B b; // expected-note {{in instantiation of}}
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};
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A<int> a; // expected-note {{in instantiation of}}
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}
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namespace test2 {
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template<typename T> struct A {
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struct B {
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struct C {};
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char c[1 + C()]; // expected-error {{invalid operands to binary expression}}
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friend constexpr int operator+(int, C) { return 4; }
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};
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B b; // expected-note {{in instantiation of}}
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};
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A<int> a; // expected-note {{in instantiation of}}
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}
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namespace test3 {
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// PR12317
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template<typename T> struct A {
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struct B {
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enum { Val = 1 };
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char c[1 + Val]; // ok
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};
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B b;
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};
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A<int> a;
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}
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namespace test4 {
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template<typename T> struct M { typedef int type; };
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template<typename T> struct A {
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struct B { // expected-note {{not complete until the closing '}'}}
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int k[typename A<typename M<T>::type>::B().k[0] + 1]; // expected-error {{incomplete type}}
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};
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B b; // expected-note {{in instantiation of}}
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};
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A<int> a; // expected-note {{in instantiation of}}
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}
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// FIXME: PR12298: Recursive constexpr function template instantiation leads to
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// stack overflow.
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#if 0
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namespace test5 {
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template<typename T> struct A {
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constexpr T f(T k) { return g(k); }
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constexpr T g(T k) {
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return k ? f(k-1)+1 : 0;
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}
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};
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// This should be accepted.
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constexpr int x = A<int>().f(5);
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}
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namespace test6 {
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template<typename T> constexpr T f(T);
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template<typename T> constexpr T g(T t) {
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typedef int arr[f(T())];
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return t;
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}
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template<typename T> constexpr T f(T t) {
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typedef int arr[g(T())];
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return t;
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}
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// This should be ill-formed.
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int n = f(0);
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}
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namespace test7 {
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template<typename T> constexpr T g(T t) {
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return t;
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}
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template<typename T> constexpr T f(T t) {
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typedef int arr[g(T())];
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return t;
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}
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// This should be accepted.
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int n = f(0);
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}
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#endif
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