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jianglk.darker
7ee447c011
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4 months ago | |
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Android.bp | 4 months ago | |
LICENSE | 4 months ago | |
MANIFEST.in | 4 months ago | |
METADATA | 4 months ago | |
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Makefile | 4 months ago | |
OTHER_BACKPORTS.md | 4 months ago | |
README | 4 months ago | |
README.md | 4 months ago | |
ipaddress.py | 4 months ago | |
setup.cfg | 4 months ago | |
setup.py | 4 months ago | |
test-python2.6.Dockerfile | 4 months ago | |
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test_ipaddress.py | 4 months ago |
README.md
ipaddress
Python 3.3+'s ipaddress for Python 2.6, 2.7, 3.2.
This repository tracks the latest version from cpython, e.g. ipaddress from cpython 3.8 as of writing.
Note that just like in Python 3.3+ you must use character strings and not byte strings for textual IP address representations:
>>> from __future__ import unicode_literals
>>> ipaddress.ip_address('1.2.3.4')
IPv4Address(u'1.2.3.4')
or
>>> ipaddress.ip_address(u'1.2.3.4')
IPv4Address(u'1.2.3.4')
but not:
>>> ipaddress.ip_address(b'1.2.3.4')
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "ipaddress.py", line 163, in ip_address
' a unicode object?' % address)
ipaddress.AddressValueError: '1.2.3.4' does not appear to be an IPv4 or IPv6 address. Did you pass in a bytes (str in Python 2) instead of a unicode object?